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Removing items from a list with $sendall
Dear $all,
I like the power of the $sendall-command, but often it is difficult to find the problem in the syntax – what am I doing wrong here:
Do iList.$sendall($ref.$remove($ref.$line),ktrue)
# ktrue is only a placeholder for the time being.
But so far, $remove does not remove anything – it needs a proper reference to what needs to be removed – – and $ref.$line does not seem to do the job…
Any ideas?
Thanks in advance!
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3 Replies
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Hi Uwe,
If you do this, you are changing the list lines in the sendall loop itself which will never work. If you use iList, then $remove can be executed (just pass 0 for the current line, you don’t need to add $ref.$line), but it will leave half the lines, just as it would if you would do this in a for-loop, because the line wich is removed will be replaced by the next line, but the loop will continue with the next line:
Do iList.$sendall(iList.$remove(0),ktrue)
It is better to use a $search to select lines and then use $remove(kListDeleteSelected).
Regards,
Marten
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Dear Marten,
Thank you for your answer!
My wish to do it in just one line of code seems to be like ‘sawing off the tree branch on which you sit’ – so I’ll do it in 2 lines as proposed by you 😉
Best regards!
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Hi Uwe,
The problem is that you cannot perform a $remove on the list line. Instead you would need to do this on the entire list.
So if we assume that no line is selected (please note this is different from the current line) then we can simply use the parameter to remove all non selected lines:
Do lList.$search(1=2) ## remove any selection
Do lList.$remove(kListKeepSelected)
Best,
Andreas
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